Question

Find the number of Aluminium and Chloride ions in 13.35 g of
Aluminium Chloride.​

Answer 1

Answer:

herefore no. Of

atoms presesnt in AlCl3=1.12 * Avogadro no. No. Of chloride atoms present in AlCl3= 3.37* Avogadro no.

Explanation:

Answer 2

Answer:

no. Of aluminium atoms presesnt in AlCl3=1.12 * Avogadro no. No. Of chloride atoms present in AlCl3= 3.37* Avogadro no.