find the number of aluminium ions and sulphate ions in 5 moles of aluminium sulphate
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Molecular mass of alumina (Al₂O) = 2 × Al³+ + 3x0² = 2 x 27 u + 3 x 16 u
<= 102 u
Gram molecular mass = 102 g
I mol of alumina (Al2O3) = 102 g
102 g of Al₂O, 1 mol
0.056 g of Al₂O3 = 1× 0.056 mol
102 = 5.49 x 10 mol
We know that one mol of alumina contains 2 mol of Al3+ ions. 5.49×10¹ mol of Al2O, contains 2x5.49x10 mol of Al³+ ions Number of Al³+ ions in 0.056 g = 2 x 5.49 x 10 x 6.022× 10² = 6.613 x 1020 ions of Al³+
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