Question

find the number of atom of each type present in 3.42 gram of cane sugar

Answer 1

Sugar cane = C12H22O11
molecular mass = 342mol
No of mole = Given mass/ molecular mass
3.42/342= 0.01
to find number of atoms 
n= N /Na
0.01= N / 6.022×10^22
0.01× 6.022×10^22=N
0.0622×10^22 amu.

that's all

@Sujeet

Answer 2

sugar cane = C12H22O11

molecular mass = 342mol

no of mol = given mass/ molecular mass

3.42/342= 0.01

to find no of atoms

n= N /Na

0.01= N / 6.022×10^22

0.01× 6.022×10^22=N

0.0622×10^22 amu mark me the braliest