find the number of atoms in 120 g of calicium and 120 g of iron which one has more number of atoms and how much is the difference
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No of atoms =mass *Avagadro's number /GMM
23
no of atoms (calcium)=120*6.023*10 /40
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No of atoms(calcium)=18.069*10
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No of atoms (Iron)=120*6.023*10 /56
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No of atoms (Iron)=12.889*10
Calcium has more atoms
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Difference between them =18.069*10
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-12.889*10
Difference =5.18
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