find the number of atoms in 2.8 liters of HCL
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Answered by
1
22.4*6.022*10^23/2.8
48.176 it may help you
48.176 it may help you
Answered by
1
According to Avogadro's law
22.4 lit of HCl contains 6.022 * 10^23 atoms
Therefore
1 lit of HCl contains = 6.02*10^23/22.4 atoms
Therefore
2.8 lit of HCl contains = 6.02*10^23 * 2.8/22.4
= 7.5275*10^18 atoms
22.4 lit of HCl contains 6.022 * 10^23 atoms
Therefore
1 lit of HCl contains = 6.02*10^23/22.4 atoms
Therefore
2.8 lit of HCl contains = 6.02*10^23 * 2.8/22.4
= 7.5275*10^18 atoms
smuni:
but in the key sheet they gave 1.5*10^23
I think in the book it is given wrong
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