Find the number of atoms of each kind present in the following
A) 5.07 gms of perchloric acid
Answers
Answered by
2
Answer:
3.04*10^22
Explanation:
Gm of perchloric Acid ÷ Molecular Weight = moles of perchloric Acid
Moles of perchloric Acid × Avogedro Number = Atom
Similar questions