Question

Find the number of atoms present in 0.016 g of
methane.
(a) 0.5 N
(b) 0.05 N,
c) No
(d) 1.6 N,
​

Answer 1

The solution of the question is in the attachment.

Answer 2

Answer:

In $0.016g$ of methane, the number of atoms present is $3.011 \times 10^{21}$ atoms.

Therefore, option c) None is the correct choice.

Explanation:

Given,

The mass of methane ($CH_{4}$), m = $0.016g$

In $0.016g$ of methane, the number of atoms present =?

As we know,

• Avogadro number = $6.022 \times 10^{23}$

Also,

• 1 mole = $6.022 \times 10^{23}$ atoms

Firstly, we have to calculate the number of moles present in methane:

• Number of moles = $\frac{Given mass}{Molar mass}$   -------equation (1)

Here,

• Given mass = $0.016g$
• The molar mass of methane, $CH_{4}$ = atomic mass of carbon + (4 × atomic mass of hydrogen)
• The molar mass of methane, $CH_{4}$ = $12 + (4\times1)$ = $16g/mol$

After putting the values in equation (1), we get:

• Number of moles = $\frac{0.016}{16}$ = $0.001 mol$

Also,

• The number of atoms present in $CH_{4}$ = $5 atoms$

Therefore,

• 1 mole = $6.022 \times 10^{23}$ atoms
• 0.001 mole = $0.001 \times 6.022 \times 10^{23}$

As there are $5 atoms$ present in methane,

• 0.001 mole = $5\times 0.001 \times 6.022 \times 10^{23}$ = $3.011 \times 10^{21}$ atoms.

Hence,

• The number of atoms present in methane = $3.011 \times 10^{21}$ atoms.