find the number of atoms present in 100 gram of iron given that atomic mass of fe
is equal to 56 u
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refer the attachment above
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In 56 g contains 6.023 x 10^23 no. of atoms
In 1 g contains = 6.023 x 10^23/56
In 100 g = 6.023 x 10^23 x 100/56
= 6.023 x 10^23 x 10^2/1000 x 56
= 6.023 x 10^23 x 10^25/10^3 x 56
= 6.023 x 10^22/56
= 107.55 x 10^22
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