Question

Find the number of atoms present in 160 grams of NaoH.​

Answer 1

Answer = 160 g of Sodium hydroxide. 160 g of Sodium hydroxide = 1 mol × 160 / 40 = 4 mol. Hence " 4 moles contained in 160 g of sodium hydroxide.

Answer 2

Answer:

hope it will be helpful

Explanation:

First, we'll convert that to moles.

Moles of NaOH = given weight (g)/ Molar mass (g.mol^-1)

= 120g/ (around) 40 g.mol^-1

= 3.

Now, we know that 1 mole NaOH contains 6.022*10^23 molecules. So 3 moles contain 3* 6.022*10^23 molecules.

If the question says 'atoms' rather that 'molecules', then It'll probably specify the element.

In this case, we have,

1 mole NaOH contains 1 mole Na+ ion. so, 6.022*10^23 atoms

1mole contains 1 mole oxygen and Hydrogen and so on.