Find the number of atoms present in 160 grams of NaoH.
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Answered by
2
Answer:
Explanation:
NaOH Sodium hydroxide
Gram molecular Mass=Mass of Na+Mass of O+Mass of H
=23+16+1
=40g
Given mass=160g
No. of moles=Gram Molecular Mass Given mass=40160=4 mol
The moles of NaOH contained in 160g of it is 4 mole
4 X 6.022 X 10 ^ 23
Answered by
8
Answer:
Given :-
weight of NaOH = 160 g
To find :-
number of atoms
Solution :-
moles of NaOH = weight of NaOH /gram molecular mass of NaOH
gram molecular mass of NaOH = mass of Na + mass of O + mass of H = 23+16+1= 40 g
moles = 160/40
moles = 4
number of molecules of NaOH = 4 NA
(NA - Avogadro's Number= 6.02 × 10^23)
atomicity of NaOH = 3
number of atoms = 3 × 4 NA
number of atoms = 12 NA
number of atoms= 12× (6.02×10^23) = 72.24 × 10^23
number of atoms in 160 g of NaOH = 7.224 × 10^24
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