Find the number of bijective functions from set A to itself when A contains 106 elements
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No of bijective functions having same no of numbers=n!
therefore 106!=106x105x104x103x?..............5x4x3x2x1
=1.04207324E+169
therefore 106!=106x105x104x103x?..............5x4x3x2x1
=1.04207324E+169
sowmyasreemajj:
Thanks a lot
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1
Answer:
step a to itself when A contains 106elements is =n!
106!
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