Question

find the number of brick of size 20cm×15 cm needed to cover the path of 45m×20m.​

Answer 1

Sum of angles of a quadrilateral ABCD = 360°

Ratio in angles = 1 : 2 : 4 : 5

Let first angle = x

Second angle = 2x

Third angle = 4x

and fourth angle = 5x

∴ x + 2x + 4x + 5x = 360°

⇒ 12x = 360° ⇒ x = 360∘12  = 30°

∴ First angle = 30°

Second angle = 30° x 2 = 60°

Third angle = 30° x 4 = 120°

Fourth angle = 30° x 5 = 150°