Math, asked by smrutissd123, 1 year ago

Find the number of bricks each measuring 25cm×12.5cm×7.5cm, required to construct a wall 6 m long, 5 m high and 50 cm thick, while the cement and mixture occupies 1/20th of the volume of the wall.

Answers

Answered by ausekararyan
7

Answer:


Step-by-step explanation:

Bricks                                    Wall


l=25 cm                                l=6 m =600 cm


b=12.5 cm                            b=50 cm


h=7.5 cm                              h=5 m =500 cm


volume of wall=l x b x h


                       =600 x 50 x 500


                       =15000000 cubic cm


volume of mixture =1/20 x 15000000


                              =750000 cubic cm


volume left =15000000 - 750000


                   =14250000 cubic cm


required brick =14250000/25 x 12.5 x 7.5


                        =6080 bricks



Answered by Anonymous
2
Bricks                                    Wall

l=25 cm                                l=6 m =600 cm

b=12.5 cm                            b=50 cm

h=7.5 cm                              h=5 m =500 cm

volume of wall=l x b x h

                       =600 x 50 x 500

                       =15000000 cubic cm

volume of mixture =1/20 x 15000000

                              =750000 cubic cm

volume left =15000000 - 750000

                   =14250000 cubic cm

required brick =14250000/25 x 12.5 x 7.5

                        =6080 bricks ans.
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