Question

Find the number of bricks with dimensions 15 cm,9 cm and 5 cm are required to build a wall of dimensions 18 m,0.5 m and 3 m​

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\bf{Given:-}\begin{cases}\sf{Dimensions\:of\: wall}\\ \sf{15cm\times 9cm\times 5cm}\\ \sf{Dimensions\:of\:wall:-}\\ \sf{ 1800cm\times 50cm\times 300cm}\end{cases}$

Now find the volumes

$\boxed{\sf{Volume\:of\:cuboid=l\times b\times h}}$

Now Volume of brick

$\sf:\implies volume\:of\: bricks=15\times 9\times 5\\ \\ \sf:\implies Volume= 15\times 45\\ \\ \sf:\implies Volume=675cm{}^{3}$

• Then the volume of wall

$\sf:\implies volume\:of\: wall=1800\times 50\times 300\\ \\ \sf:\implies Volume= 1800\times 45000\\ \\ \sf:\implies Volume=27,000,000cm{}^{3}$

Now the. No. of bricks required

$\boxed{\sf{Bricks\: required=\dfrac{Volume\:of\:wall}{Volume\:of\:bricks}}}$

$\sf:\implies bricks\: required=\cancel{\dfrac{27000000}{675}}\\ \\ \sf:\implies Bricks\: required=40,000$

Brick's Required to build the wall is 40,000

Answer 2

Solution

There would be 40,000 bricks in the wall

Given

• Dimensions of the bricks are 15 cm × 9 cm × 5 cm

• Dimensions of the wall are 18 m × 0.5 m × 3 m

To finD

No.of bricks which will make up the walll

$\huge{\boxed{\boxed{\sf Volume \ Of \ Cuboid = l \times b \times h}}}$

Volume of the Brick

$\sf \: V_B = 15 \times 9 \times 5 \\ \\ \longrightarrow \: \sf \: V_B = 675 \: {cm}^{3}$

Volume of the Wall

The dimensions of wall are givien in metres while the dimensions of brick are given in centimetres

➠ The dimensions would be 1800 cm × 50 cm × 300 cm

Thus,

$\sf \: V_W = 1800 \times 50 \times 300 \\ \\ \longrightarrow \sf \: V_W = 27000000 \: {cm}^{3}$

Let the there be n number of bricks

$\implies \: \sf \: V_W = n \times V_B \\ \\ \implies \: \sf \: n = \dfrac{2700000}{675} \\ \\ \huge{ \implies \: \boxed{ \boxed{ \sf \: n = 40000}}}$