Find the number of Ca²⁺ ions in 3×10⁻³ g of CaCO₃.
Answers
Answered by
1
Answer:
Answer
Correct option is
B
3.44×10
22
ions
Given 3.2g CaO
atomic mass = 40+16
=56
moles of Ca ion =
56
3.2
=0.057
1 mol = 6.022×10
23
atoms of Ca ion
0.057mol=3.44×10
22
Ca ions
Answered by
0
Answer:
Explanation:
Ca 2
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