Find the number of Cations in 51g of Aluminium Oxide. (Aℓ = 27, O = 16)
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Answer:
Aluminium Oxide formula is Al2O3
molar mass of Al2O3 = 102g/mol
given, 51 g
therefore no of moles = 51/102 = 0.5 mol
no of Al2O3 molecules in 0.5 mol = 0.5 Na
now one Al2O3 molecule contains 2 Al3+ cations
no of cations in 0.5 Na molecules = 0.5Na * 2 = Na = 6.022*10^23 cations
Explanation:
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