Question

Find the number of cl atom present in 0.71 g of it

Answer 1

Answer:

Correct option is

C

1.205×10

24

atoms

Weight of Cl

2

=71 g

Molecular weight of Cl

2

=71 g/mol

Number of moles of Cl

2

=

71 g/gatom

71 g

=1 moles.

The Avogadro's number is 6.023×10

23

molecules/mol.

The number of atoms of Cl

2

=2 atoms/molecule ×1 mol ×6.023×10

23

molecules/mol

=1.205×10

24

atoms

SORRY FOR BEING LATE TO GIVE YOUR ANSWER