find the number of coins, 1.5 cm diameter and 0.2 cm thick,to be melted to form a right circular cylinder with a height of 10 cm and a diameter of 4.5 cm.
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let n is the number of coins
according to question
volume of cylinder =volume of n coins
pi.R^2H=n x pi.r^2.h
R^2.H=n.r^2.h
n=R^2H/r^2.h
now put H=10cm
R=4.5/2 cm
r=1.5cm
h=0.2cm
hence no of coins =450
according to question
volume of cylinder =volume of n coins
pi.R^2H=n x pi.r^2.h
R^2.H=n.r^2.h
n=R^2H/r^2.h
now put H=10cm
R=4.5/2 cm
r=1.5cm
h=0.2cm
hence no of coins =450
Answered by
0
Answer:
let n is the number of coins
according to question
volume of cylinder =volume of n coins
pi.R^2H=n x pi.r^2.h
R^2.H=n.r^2.h
n=R^2H/r^2.h
now put H=10cm
R=4.5/2 cm
r=1.5cm
h=0.2cm
hence no of coins =450
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