Find the number of coins 1.5 cm in diameter and 0.2cm thick to be melted to form a right circular cylinder of height 16cm and diameter 6cm
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Answered by
15
volume of cone ⅓pir²h
=⅓×22/7×3×3×16
=150.85
volume of coin , coin in the shape of cylinder so, pi r²h
= 22/7×0.1×0.1×1.5
=0.047
150.85/0.047
=3209
=⅓×22/7×3×3×16
=150.85
volume of coin , coin in the shape of cylinder so, pi r²h
= 22/7×0.1×0.1×1.5
=0.047
150.85/0.047
=3209
Answered by
0
Hola mate
Here is your answer -
As the coins are in the form of thin cylinder
Volume of each coin = π×(0.75)²×0.2 =0.1125π cm³
Volume of melted cylinder = π× (2.25)²× 10 = 50.625π cm³
number of coin required = (volume of melted cylinder)/(volume of each coin)
= 50.625π/0.1125π = 450 coins
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