Question

find the number of coins 1.5cm in diameter and 0.2 cm thick to be melted to form a right circular cylinder of height 16 and diameter 6cm​

Answer 1

$\Huge \fbox \green{Solution}$

Each one of those coins is also a cylinder (just a very very short one), and its volume is

V = πr²h = π(.75)²(.2) = 9π/80 cm³

The right circular cylinder has volume V = π(2.25)²(10) = 405π/8 cm³.

Divide the larger cylinder's volume by the volume of each coin = (405π/8) / (9π/80) = 450 coins

Answer:450 coins

$\mathfrak{Hope \: \: it \: \: Helps!}$

Answer 2

Step-by-step explanation:

• V = πr²h = π(.75)²(.2) = 9π/80 cm³

• The right circular cylinder has volume V = π(2.25)²(10) = 405π/8 cm³.

• Divide the larger cylinder's volume by the volume of each coin = (405π/8) / (9π/80) = 450 coins.

Hope it helps uhh and sorry if any mistake found ❤❤