Math, asked by tiyathomas3544, 10 months ago

Find the number of coins 1.5cm in diameter and 2mm thick to be melted to form a right circular cylinder of height 10cm and diameter 4.5cm

Answers

Answered by 24541278r
1

n*(pi)(1.5/2)^2*(0.2) = (pi)(4.5/2)^2*(10)

n = 202.5/2.25 = 90

Answered by samijain1069
7

Answer:

No. of coins=450 coins

Step-by-step explanation:

As the coins are in the form of thin cylinder

Volume of each coin = π×(0.75)²×0.2 =0.1125π cm³

Volume of melted cylinder = π× (2.25)²× 10 = 50.625π cm³

number of coin required = (volume of melted cylinder)/(volume of each coin)

                                 = 50.625π/0.1125π = 450 coins

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