find the number of coins 2m in diameter and 0.5cm thick to be melted to form a right circular cylinder of height 10cm and radius 3.5cm
Answers
Answer:
245 coins the diameter will be 2 cm
Step-by-step explanation:
volume of coin
πr^2h
=22/7*(1)^2*0.5
=11/7 cm
now volume of circular cylinder
πr^2h
=22/7*(3.5)^2*10 on simplifying this we will get
=22*122.5/7
now divide the volume of cylinder with the volume of coin and you will get the no. of coins
22*122.5/7 * 7/11 here 7 and 7 will get cancelled
11*2=22
we are left with 2*122.5=245 coins Ans
Answer:245 coins the diameter will be 2 cm
Step-by-step explanation:
volume of coin
πr^2h
=22/7*(1)^2*0.5
=11/7 cm
now volume of circular cylinder
πr^2h
=22/7*(3.5)^2*10 on simplifying this we will get
=22*122.5/7
now divide the volume of cylinder with the volume of coin and you will get the no. of coins
22*122.5/7 * 7/11 here 7 and 7 will get cancelled
11*2=22
we are left with 2*122.5=245 coins Ans
Step-by-step explanation: