Find the number of coins of 1.5 cm diameter and 0.2 cm thickness to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm.
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Here, as the coins are melted into the form of a right circular cylinder, so we have to divide the volume of cylinder by the volume of coins.
Diameter=1.5 cm
So radius=1.5/2
=0.75 cm
Thickness (height)=0.2 cm
So, volume of coins=πr^2h
=π×0.75^2×0.2
=9π/80 cm^3
Now, diameter of cylinder=4.5 cm
So radius=4.5/2 cm
=2.25 cm
Height=10 cm
So its volume=πr^2h
=π×2.25^2×10
=405π/8 cm^3
Now,number of coins =405π/8÷9π/80
=450
Diameter=1.5 cm
So radius=1.5/2
=0.75 cm
Thickness (height)=0.2 cm
So, volume of coins=πr^2h
=π×0.75^2×0.2
=9π/80 cm^3
Now, diameter of cylinder=4.5 cm
So radius=4.5/2 cm
=2.25 cm
Height=10 cm
So its volume=πr^2h
=π×2.25^2×10
=405π/8 cm^3
Now,number of coins =405π/8÷9π/80
=450
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