find the number of coins of 1.5 CM X 0.2 CM thickness to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 CM
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height of coin= 0.2 cm
radius of coin = 1.5cm
v(cylinder)= πr²h =22/7 × 1.5 ×1.5 × 0.2 = 1.413 cm³
height of cylinder = 10 cm
radius of cylinder = d/2 = 2.25 cm
v(cylinder) = πr²h = 22/7 × 2.25 × 2.25 × 10 =158.9625 cm³
number of coins = v(cylinder)/v(coin) = 158.9625/1.413 = 112.5
so 112.5 coins can be made from the cylinder.
radius of coin = 1.5cm
v(cylinder)= πr²h =22/7 × 1.5 ×1.5 × 0.2 = 1.413 cm³
height of cylinder = 10 cm
radius of cylinder = d/2 = 2.25 cm
v(cylinder) = πr²h = 22/7 × 2.25 × 2.25 × 10 =158.9625 cm³
number of coins = v(cylinder)/v(coin) = 158.9625/1.413 = 112.5
so 112.5 coins can be made from the cylinder.
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0
Hello!
First of all we have to find Volume of each coin.
Therefore,
Volume of each coin = π×(0.75)²×0.2 =0.1125π cm³
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Now,
Volume of melted cylinder = π× (2.25)²× 10 = 50.625π cm
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number of coin required =(volume of each coin)/ (volume of melted cylinder)
number of coins required = = 50.625π/0.1125π
no of coins = 450 coins
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450 coins
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