Question

Find the number of coins of 2.5 cm diameter and 0.2 cm thickness to be melted to form a right circular cylinder of height 10 cm and diameter 5.5 cm.


plz solve this question plz​

Answer 1

Answer:

Let n be the number of 1.5 cm diameter coins required to form a right circular cylinder of height 10 cm and diameter 4.5 cm.

Now,

Volume of right circular cylinder =n× volume of 1.5 cm diameter coin.

Therefore,

 n=π(21.5)2×102π(24.5)2×10

=20×2045×45×15×15×210×20×20×10

=9×10×5

=450

Step-by-step explanation:

it's wrong but u can do it in same way just change the number

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Answer 2

Step-by-step explanation:

Let n be the number of 1.5 cm diameter coins required to form a right circular cylinder of height 10 cm and diameter 4.5 cm.

Now,

Volume of right circular cylinder =n× volume of 1.5 cm diameter coin.

Therefore,

n=

π(

2

1.5

)

2

×

10

2

π(

2

4.5

)

2

×10

=

20×20

45×45

×

15×15×2

10×20×20×10

=9×10×5

=450

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