Question

Find the number of coins of 2.5 cm diameter and 0.2 cm thickness to be melted to form a right circular cylinder of height 10 cm and diameter 5.5 cm.
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Answer 1

Answer:

Let n be the number of 1.5 cm diameter coins required to form a right circular cylinder of height 10 cm and diameter 4.5 cm.

Now,

Volume of right circular cylinder =n× volume of 1.5 cm diameter coin.

Therefore,

$n \: = \frac{\pi \: \binom{4.5}{2} {}^{2} \times 10}{\pi \: \binom{1.5}{2} {}^{2} \times \frac{2}{10} }$

$= \: \frac{45 \times 45}{20 \times 20} \times \frac{10 \times 20 \times 20 \times 10}{15 \times 15 \times 2}$

$= \: 9 \: \times \: 10 \: \times \: 5$

$= \: 450$

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Answer 2

Answer:

sorry dont know

Step-by-step explanation:

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