Question

find the number of common solution for the system of linear
5x+4y+6=0
10x+8y=12​

Answer 1

Answer:

Clearly both the equations are parallel to each other as

10x+8y=12=>2(5x+4y=6)

which has the same coefficients of x and y as 5x+4y+6=0

Two parallel lines never intersect and do not have any solutions.

So, the number of common solutions for the given system of linear equations is 0.

Answer 2

Answer:

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