find the number of consecutive zeros in2³× 5⁴× 3⁵
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Answer:
I don't know sorry sis
Step-by-step explanation:
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Hey friend!
Here is your answer:
To find the number of consecutive zeros in 2³× 5⁴× 3⁵
We know that 2¹ × 5¹ = 10 → 1 zero
and 2² × 5² = 10² = 100 → 2 zeros
similarly 2³ × 5³ 10³ 1000 → 3 zeros
thus, 2ⁿ × 5ⁿ = 10ⁿ → n zeros
Hence, common power of 2 and 3 → 3
→ 3 zeros
I hope it helps you and if you appreciate my answer, please respond with a thanks
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