Question

find the number of diagonal drawn from a vertex in a decagon.(Hint:A hexagon has 10 sides)​

Answer 1

Answer:

Decagon = 10 sides polygon

Let's assume you are talking about a Decagon with all of its vertices going outward (is all of its angles are less than 180°)

So as it has 10 vertices, so, each vertices can start an arrow towards remaining 9 vertices. But 2 of those won't be called diagonals as those are sides (line between 2 adjacent vertices, both sides will be called sides). So each of the 10 vertices will 9–2=7 diagonals.

Thus 10×7=70 diagonals

But wait, 1 diagonal is between two vertices, so 1 diagonal has been counted twice in this calculation, so actual diagonal count is: 70/2=35

hope it may help u...

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Answer 2

Answer:

First of all there is mistake in hint.

A decagon has 10 sides . A hexagon has six sides.

No of diagonals in a Quadrilateral = n(n-3)/2

Hence decagon has 10(10-3)/2 = 35 sides.

your ans is 35 sides.