find the number of diagonal of different polygon. n=4 to n=10. (Quadrilateral to Decagon)..Formula, No. of diagonals =n(n-3) Please give me the answer
Answers
Answered by
1
Answer:
n(n-3)/2
Step-by-step explanation:
n(n-3)/2
(1) 4(4-3)/2 = 4/2 = 2
(2) 10(10-3)/2 = 10*7/2 = 70/2 = 35
Answered by
0
here is your answer beautiful.
❤❤❤❤❤❤❤❤❤❤
to find the number of diagonals we just have to put the value of n in the formula.
(1) n= 4.so,
n=4(4-3)/2
n=(16-12)/2
n= 4/2
n= 2
(2)n = 10
n = 10(10-3)/2
n = (100 - 30)/2
n = 75/2
n = 35
Similar questions
English,
6 months ago
English,
6 months ago
English,
1 year ago
History,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago