Find the number of digits in 12 to the power 12 if log 2 to the base 10 =0.3010 log 3 to the base 10 =0.4771
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Answered by
0
Answer:
13
Step-by-step explanation:
number of digits in 12^{12}12
12
is given by
\left\lfloor\log_{10}12^{12}\right\rfloor+1⌊log
10
12
12
⌋+1
=\left\lfloor12\log_{10}(4\times3)\right\rfloor+1=⌊12log
10
(4×3)⌋+1
=\left\lfloor12\left(2\log_{10}2+\log_{10}3\right)\right\rfloor+1=⌊12(2log
10
2+log
10
3)⌋+1
=\left\lfloor12\left(2(0.3010)+0.4771\right)\right\rfloor+1=⌊12(2(0.3010)+0.4771)⌋+1
=\left\lfloor12.9492\rfloor+1
=12+1=12+1
=13=13
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