Find the number of digits in 4 ^ 2013 if, log 2 to the base 10 = 0.3010 ? i will mark u as brainliest
Answers
Answered by
6
4^2013 = 2^4026.
No of digits = [4026 log 2] + 1
=[4026 x 0.3010] + 1
=[1211.8260]+1
= 1211 + 1
= 1212.
So, the answer is 1212.
if you like this please mark it as brainliest and follow me
No of digits = [4026 log 2] + 1
=[4026 x 0.3010] + 1
=[1211.8260]+1
= 1211 + 1
= 1212.
So, the answer is 1212.
if you like this please mark it as brainliest and follow me
yogendra1024:
please mark it as brainliest
Similar questions