Question

Find the number of digits in 810, given that log 2 = 0.301

A)10
B)20
C)30
D)None of these

Answer 1

Step-by-step explanation:

D). none of these iska ans

Answer 2

The number of terms in $8^{10}$ is 10.

Step-by-step explanation:

We have log 2 = 0.301.

Now, we have to find the number of digits in $8^{10}$.

Now, $\log 8^{10} = 10 \log 8 = 10 \log 2^{3} = 30 \log 2 = 30(0.301) = 9.03$ ............. (1)

Since we know the property of logarithmic function as $\log a^{b} = b \log a$

So, $8^{10} = 10^{9.03}$ {From equation (1)}

{Converting logarithm to exponential form }

Therefore, the number of terms in $8^{10}$ is 10. (Answer)