Math, asked by aadarshdimri0218, 1 year ago


Find the number of digits in the square root of each of the following numbers (without
any calculation)
(i) 64
(ü) 144
(iii) 4489
(iv) 27225
(v) 390625
64​

Answers

Answered by Agastya0606
36

Given: The digits (i) 64  (ü) 144  (iii) 4489  (iv) 27225  (v) 390625

To find: The number of digits in the square root of each of the following numbers.

Solution:

  • Now we know the formula for number of digits in the square root .
  • If even terms in digits, then:

              n/2

  • If odd terms in digits, then:

              n+1/2

  • So taking the numbers now, we get:

               (i) 64  

              n = 2, so:

              2/2 = 1

              One digit in square root.

              (ü) 144

              n = 3, so:

              3+1/2 = 2

              Two digit in square root.

               (iii) 4489  

              n = 4, so:

              4/2 = 2

              Two digit in square root.

              (iv) 27225  

              n = 5, so:

              5+1/2 = 3

              Three digit in square root.

              (v) 390625

              n = 6, so:

              6/2 = 3

              Three digit in square root.

Answer:

              So the the number of digits in the square root of each of the following numbers is given in the solution part.

Answered by sahanuj703
11

Step-by-step explanation:

(1). No. of digit in 64=n=2

since, n is even

:; Number of digit in square root=n/2

=2/2

=1

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