Question

find the number of digits in the square roots of the following number is 81​

Answer 1

Answer:

1

Step-by-step explanation:

$\sqrt{81} = 9$

9is single digit

Answer 2

It is very simple.

If it is an even no. Then let the no. Of digits be n

No. Of digits in it's square root would be (n/2)

Or

If it is a odd no. Then,

(N+1/2) in this case it is even. So (n/2) 8,1 2/2= 1

1 digit