Find the number of divisors of 42336 excluding 1 and the number itself. Find the sum of these divisors.
Answers
Answered by
0
Answer:
1678
Step-by-step explanation:
Given number is 38808
It can be expressed as
(2)
3
×(3)
2
×(7)
2
×(11)
⇒ Total number of factors
=(4+1)(2+1)(3+1)(3+1)(6+1)−2
=5×3×4×4×7−2
=1880−2
On subtracting we get 1678
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Answered by
1
Given number is 42336
Let first find the prime factorization of 42336.
Thus, Prime factorization of
We know,
If any natural number 'n' is represented as its prime factorization as
So,
Here ,
It implies number of divisors of 42236 is given by
And to find the number of divisors exclusive of 1 and number itself,
Then,
Number of divisors = 72 - 2 = 70.
Now, To find the sum of divisors.
Again, Prime factorization of 42336 is
So, sum of divisors is
So,
Sum of proper divisors = 143640 - 1 - 42336 = 101303
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