Question

Find the number of elections present in 180gm of H₂O ​

Answer 1

Answer:

180 grams water is 10 molesSo, no. of molecules of water in 10 moles would be = no. of moles× 6.022×10^23=10×6.022×10^23=60.22×10^23=6.022×10^24No. Of electrons = no. of molecules×no. of electrons in one molecule

H2O contains 2+8=10 electrons