Question

find the number of electron present in 16C of charge. (Q=1.6×10^-19)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\huge \mathtt{ \fbox{Solution :) }}$

Given ,

Charge = 16 C

Electron = 1.6 × 10^-19 C

We know that , the total charge of a body is integral multiple of electrons

$\large \mathtt{ \fbox{Q = ne}}$

Substitute the known values , we get

$\sf \mapsto 16 = n \times 1.6 \times {(10)}^{ - 19} \\ \\ \sf \mapsto n = 1 \times {(10)}^{20}$

Hence , the number of electrons is (10)^20

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