Find The Number Of Electron that Cross A Conductor Of Length To 30m with an Average Speed Of 15 Ms When Ammeter Show's A Reading Of 1.6A
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Answer:
n=
Explanation:
length of wire = 30m
Current= 1.6A
Time = 2 min (avg speed is given)
charge = current ×time
Q=1.6× 120
Q= 192
Q=ne
n=no of e
e=charge of e
192 =n×1.6×10^-19
n=
calculate this will be your answer
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