Find the number of electrons involved in the electrodeposition of 63.5 of copper from a solution of copper sulphate
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I have a look at the moment and the family of four
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Explanation:
This is a redox reaction, meaning reduction-oxidation reaction.
First, we have to find the oxidation number of Cu in CuSO4:
(oxidation number of Cu)+ (oxidation number of S) + 4(oxidation number of oxygen) = 0
(oxidation number of Cu) + (6) + 4(-2) = 0
oxidation number Cu = 2+
CuSO4 ---> Cu + SO42-
Cu2+ + SO42- ----> Cu + SO42-
Cu2+ -----> Cu + 2e- (net ionic reaction)
The stoichiometric equation would be 2 electrons per mole Copper. Copper has a molar mass of 63.5 g/mol.
Then, it would only need 2 electrons.
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