Question

Find the number of electrons passing in 1 s through the cross-section of a conductor if a current of 2uA is flowing through it.​

Answer 1

Answer : The number of electrons passing through a cross section of conductor in 1 sec is 12.5 × 10¹²

Explanation:

Current flowing through a cross section of a conductor = 2μA ( given )

To find = Number of electrons passing through cross section of conductor in 1sec.

So , I = Q / T

Where I = current flowing through conductor

Q = charge

T = Time in sec.

∴ 2 × 10⁶ = Q / 1

∴ 2 × 10⁶ = n × e ( n= no of electrons & e = 1.6 × 10-¹⁹ )

∴ 2 × 10⁶ = n × 1.6 × 10-¹⁹

∴ 2 × 10⁶ / 1.6 × 10-¹⁹ = n

n = 12.5 × 10¹²

Answer 2

Answer:

The number of electrons passing in 1 s through the cross-section of a conductor if a current of 2uA is flowing through it is $3.75*10^{13}$

Explanation:

• The electric current is the division of charge flowing to time of passing the charges

• If (n) number of charged particles with charge (q) moving through a cross-section within a time (t), then

        current $I=nq/t$

From the question, we have

the current through the conductor $I=6*10^{-6}A$

time of passing $t=1s$

charge of an electron $q=1.6*10^{-19}C$

rearrange the terms to get the number of electrons

$n=It/q$

$n=\frac{6*10^{-6} *1}{1.6*10^{-19} } =3.75*10^{13}$