Question

Find the number of electrons present in 16g of Methane

Answer 1

Answer:

Explanation:

1 molecule of CH4 contains 6+4(1)=10 electrons

Avagadro number of molecules are equal to 1 mole.

So,

1 mole of CH4 contains 10*avagadro number of electrons

1 mole of methane gas weighs 12+4(1)=16 grams

Therefore,

16 grams of CH4 contains 10*6.023*10^23 electrons = 6.023*10^24 electrons.