Question

Find the number of electrons present in 5 C of charge.

Answer 1

Answer:

3125×10^15 electrons

Explanation:

Q=ne ( n=no.of electrons ,e= charge of electrons, Q =given charge)

n=Q/e

n=5/1.6×10^-19

n=3125×10^15 electrons

Answer 2

Use the equation Q = ne

where, Q is the charge

n is the number of electrons

e is the electronic charge

Here,

Q = 5C

e = 1.6 × 10^-19

n = Q/e = 5/1.6×10^-19 = 3.125×10^19 electrons

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