Question

find the number of electrons whose mass is equal to the total mass of neutrons present in one calcium atom

Answer 1

Explanation:

mass of one netron = 1.67×10^-27 kg

total no of neutrons in Ca atom = ATOMIC MASS - NO OF PROTONS ( atomic no)

40-20 =20 neutrons

mass of 20 neutrons = 20×1.67×10^-27= 33.4×10^-27 kg

Given mass of n electrons = total mass of neutrons in Ca atom

ne^-= 33.4×10^-27 kg

mass of one electron 9.1×10^-31 kg

n= 33.4×10^-27÷9.1×10^-31

n = 3.67×10^4 e^-

hope you understand