Find the number of elements of the power set of P.
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For a given set S with n elements, number of elements in P(S) is 2^n. As each element has two possibilities (present or absent}, possible subsets are 2×2×2.. n times = 2^n. Therefore, power set contains 2^n elements
k = 2 x 1^2= 2
l = 2 x 2^2 = 8
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