Question

Find the number of equally sized tiles of dimension 6m by 3 m required for covering a floor
of size 30 m by 15 m.​

Answer 1

Answer:

210 Tiles "Hope it Helps You"☺

Step-by-step explanation:

A (tile) = (30 cm)(30 cm) = (0.3 m)(0.3 m) = 0.09 sq. m

No of tiles = A(total)/A(tile) = (18.9 sq. m)/(0.09 sq. m/tile) = 210 tiles

Answer 2

Answer:

25 tiles required

Step-by-step explanation:

Area of tiles 6×3=18

Area of floor 30×15=450

Therefore, 450/18

=25