Question

Find the number of equivalents of solute present in 123 ml of 1 N KOH solution

please help me​

Answer 1

Answer: Molarity=  

GMW of KOH

Weight of KOH

​

×  

Vol(ml)

1000

​

             

[GMW of KOH= Atomic weight of K+ atomic weight of O+ atomic weight of H=10+16+1=27]

⇒0.1=  

27

Weight of KOH

​

×  

100

1000

​

                         

Weight of KOH=  

10

2.7

​

 

Weight of KOH=0.27 g

Explanation:

Answer 2

Answer:

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