Math, asked by hyd1758, 5 months ago

find the number of even integers between -11 and -17

Answers

Answered by gunjanmaulik2010
0

Answer:

There are 3 even integers.

Step-by-step explanation:

They are -12, -14, -16

Answered by Legend42
8

Answer:

10 are, in general, the possible digits (0, 1, 2, 3, 4, 5, 6, 7, 8, 9).

In the range (10000–19999) we have 1 integer (1) for the 1st digit, 5 possible integers (0, 2, 4, 6, 8) for the 5th digit, (10–2=)8 possible integers for the 2nd digit, 7 for the 3rd and 6 for the 4th; i.e. 1*8*7*6*5=1680. Similar situation for the ranges (30000–39999) and (50000–59999).

In the range (20000–29999) we have 1 integer (2) for the 1st digit, 4 possible integers (0, 4, 6, 8) for the 5th digit, (10–2=)8 possible integers for the 2nd digit, 7 for the 3rd and 6 for the 4th; i.e. 1*8*7*6*4=1344. Similar situation for the range (40000–49999).

In the range (10000–59999) the even integers having no digits repeated are: 3*1680+2*1344 = 7728, i.e. 7728/25000=0,30912 if referred to all the even numbers of the range.

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