Question

find the number of even positive integers which have three digits.​

Answer 1

Answer:

first 3 digit even number =

a = 100

an = 998

d = 2

an = a + (n-1)d

998=100+ (n-1)2

888=(n-1)2

n-1= 888/2

n-1 = 444

n = 445

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