Question

Find the number of even positive integers which have three digit​

Answer 1

Answer:

(a) Choosing 0 for the units leaves all 9 nonzero digits available for the hundreds digit. (The hundreds digit must be nonzero, otherwise the number wouldn't be considered a "three-digit number".) Each of those choices leaves 8 digits to choose for the tens digit to get no duplication. SO 9*8 = 72 different numbers are possible.

(b) choosing a nonzero units digit has 4 possibilities (2, 4, 6, 8 since the number must be even). Each of those leaves only 8 choices for the hundreds digit (one nonzero digit was taken, each time) and each of those has 8 choices left for the tens digit. 4*8*8 = 256 different numbers.

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Answer 2

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